sinA = cosA-coA.cos2A-(1/2)sin2A sin2A-cosA ALSO 8sinA.cosA.cos2A.cos4A = sin8A how do you do these? and can u explain the 2nd one as well ... thanks
Follow Math Help Forum on Facebook and Google+
Use and .
yeah i know that silly, but how i do it. haha
Hello, Jono Mathematician! Wingless suggested a few identities: . . . . We must find ways to apply them . . . The left side is: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
View Tag Cloud