An SAS triangle can't have two solutions... but this one is strange
<A = 34 degrees. b=24. c=46.
This is an SAS triangle... when I use Law of Cosines, I solved for side a and got a=29.35.
Then I tried using Law of Sines to solve for <B and <C.
If I solve for <B first, I set it up this way:
and I get <B=27.2 degrees. Which means <C=118.8 degrees.
However, if I solve for <C first, I set it up this way:
and I get <C=61.2 degrees. Which means <B=84.8 degrees.
What is going on?! I know I'm missing something here, but I can't figure out what it is!