<A = 34 degrees. b=24. c=46.
This is an SAS triangle... when I use Law of Cosines, I solved for side a and got a=29.35.
Then I tried using Law of Sines to solve for <B and <C.
If I solve for <B first, I set it up this way:
sin(34)
-------
29.35
=
sin B
--------
24
and I get <B=27.2 degrees. Which means <C=118.8 degrees.
However, if I solve for <C first, I set it up this way:
sin(34)
-------
29.35
=
sin C
--------
46
and I get <C=61.2 degrees. Which means <B=84.8 degrees.
What is going on?! I know I'm missing something here, but I can't figure out what it is!
Please help!
Thanks for the reply, but I don't think my question has been answered.
Obviously, <C must be the largest of my two choices; it's opposite the largest side. Choosing the smaller <C would make no sense, visually.
My question is why I have two choices for <C to begin with! This is an SAS triangle. Shouldn't there only be one option for my missing information?
For what reasons can I dismiss the smaller C? Is there any mathematical reason I'm even coming up with that answer in the first place?
It's because your calculator is picking it up in the first quadrant rather than the second. If you remember your good ole unit circle, you understand the sine of say. . . 60 degrees will be the same as the sine of 120 degrees. When you take that inverse sine in the end it is giving you a right answer, just in the wrong quadrant.
Check this out: 90-61.2=28.8
118.8-90=28.8
Do you dig that? I know the best way to avoid this with an SSS triangle is to always solve for the biggest angle first. I hope you sort of understand now and can get around this in the future.