hi to all i would like some help on the that math project
Note that angle QAB has measure 90 - x.
Also, cos(QAB) = QB/AB = QB/18, so QB = 18(cos(90-x)).
Similarly, cos(CBR) = BR/27, so BR = 27(cos(x)).
Note that QB + BR = 30 (the bottom part of your diagram).
So, 18(cos(90-x)) + 27(cos(x)) = 30.
Use the fact that the graph of cosine is the same as the graph of sine (just shifted) to convert cos(90-x) to sin(x).
Finally, divide everything by 3.
Hello, carlasader!
We have: .a) Prove that: .
Note that: .
In right triangle
We have .
In right triangle
Since
. . we have: .
This takes a bit of work . . .b) Express in the form:
. . where
. . giving the values of to 2 decimal places.
If you've never seen this done, no wonder you are baffled.
We have: .
. . Find: .
Multiply and divide by
. . and we have: .
Let
. . and we have: .
Hence: .
And: .