Prove that:
Multiply top and bottom inside the bracket on the left hand side by the
complex conjugate of what is on the bottom:
multiply top and bottom inside the bracket by :
Then DeMoivre's theorem gives:
RonL
Hi,
Can someone tell me the step by step solution of question in the attachment ASAP.
Note that i am a beginner and want to learn it before going to next standard.
Step by step solution will help me in understanding.
Thanks in advance
Lalit Chugh
CaptainBlack likes to complain how I make some solutions too complicated, well now I can complain he makes the solution too complicated.
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Remember that,
You have,
Thus, using co-function identities,
Thus,
Using the rule,
You have, (watch those signs )
Thus,
By de-Moiver's theorem,
Measured in lines of TeX I make the count 6 lines in my post (I'mOriginally Posted by ThePerfectHacker
not counting the first its just the statement of the problem so I
can see where I am going - I hate problems in attachments I like
to be able to see them without clicking).
The count in PH's post is 8, so by that measure mine is less complex
RonL
Hello, killer baby!
If u dnt knw DeMoivre's Theorem, u shudn't b workn on dis problem.is dere any other method widout using demoivre's theroem as i dnt knw dis theorem.
if you can guyz pls explain me d theorem or try to find out a different way.
The only alternative is to expand everything . . . and simplify
. . . but it's very very long and tedious.
The numerator is: .
. .
. .
. .
. .
. .
. .
Now u wrk on da denominator . . .
If u say, "Howja du dat?", Ive totally wasted my time . . .