i dont get how sqrt 3/3 in a 30-60-90 triangle in reference to the unit circle, is part of it...i dont know if that make sense...
because i know that 1/2 and sqrt 3/2 and the hypotenuse 1 is a 30-60-90.
and how do you know sqrt 3/3 is pi/6?
Imagine the unit circle. A point (x, y) has coordinates . As the angle gets smaller and smaller the point on the unit circle gets closer and closer to (1, 0). Which means that and .Originally Posted by >_<SHY_GUY>_<
Think of the tangent problems backward.
so
.
The other inverse tangent problems follow a similar logic.
The 30 - 60 - 90 triangle contains a 30 degree angle. tan(30) = sqrt(3) / 3. You are thinking of either sin(60) or cos(30), which are both sqrt(3) / 2.
-Dan
i dont get how sqrt 3/3 in a 30-60-90 triangle in reference to the unit circle, is part of it...i dont know if that make sense...
because i know that 1/2 and sqrt 3/2 and the hypotenuse 1 is a 30-60-90.
and how do you know sqrt 3/3 is pi/6?