My favorite:
It's a lot easier with only one function.
'Solve sin x + 4 cos x = 3'
Can anyone help me with the above problem? Trigonometric identities and formulae confuse me.
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I have tried doing this:
sin x = 3 - 4 cos x
divide all by cos x
then tan x = 3/cos x - 4
rearrange so 4 = 3/cos x - tan x
which is same as 4 = 3 sec x - tan x
square both sides
so 16 = 9 sec^2 x - tan^2 x
this is 16 = 9(tan^2x + 1) - tan^2 x
and 16 = 9tan^2x - tan^2x + 9
rearrange so 7 = 8 tan^2 x
7/8 = tan^2 x
so tan x= sqrt(7/8)
and x = arctan sqrt(7/8)
Is this correct?
If anyone could provide any help or solution to this problem, I'll be so grateful.
Thank you!
Herman