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Math Help - Trigonometry, solving for between 0 and 360

  1. #1
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    Trigonometry, solving for between 0 and 360

    Hi!

    I'm trying to solve θ between 0 and 360

    I know that if Sinθ = 0.7 then θ = 44.4 (because sin^-1(0.7)= 44.4 to 1.d.p)

    I know this for Cos and Tan but how do I solve for Cosec, Cot and Sec?

    In particular the questions im looking at are:

    1) Cosecθ = 2.3
    2) Cotθ = -4.26
    3) Secθ = 1.5

    Im not really looking for the answers but the method itself, thank you!
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    You could

    Quote Originally Posted by Nick87 View Post
    Hi!

    I'm trying to solve θ between 0 and 360

    I know that if Sinθ = 0.7 then θ = 44.4 (because sin^-1(0.7)= 44.4 to 1.d.p)

    I know this for Cos and Tan but how do I solve for Cosec, Cot and Sec?

    In particular the questions im looking at are:

    1) Cosecθ = 2.3
    2) Cotθ = -4.26
    3) Secθ = 1.5

    Im not really looking for the answers but the method itself, thank you!
    Do one of two things...just take the arcsc,arcot,arsec or use the theorem that for he co-functions you just reciprocate the \theta...example tan(\theta)=cot\bigg(\frac{1}{\theta}\bigg)...also note the converse works cot(\theta)=tan\bigg(\frac{1}{\theta}\bigg)
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Oh yeah

    and arcsec(x)=sec^{-1}(x) as for all of the arc things..if you were unfamiliar with that notation
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