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Math Help - solving trig equations

  1. #1
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    solving trig equations

    I have a few problems that I just can't figure out how to deal with at all.

    Solve for all answers in radians:

    1. 1-sin(t) = sqrt3(cos t)

    2. cos(x) - sin(x) = 1

    (I know that one's really simple, but I don't know how to set it up.)

    3. 2tan(t) - sec^2(t) = 0

    4. tan(x) + sec(x) = 1

    5. cot(a) + tan(a) = csc(a)sec(a)

    6. sec^5(x) = 4sec(x)


    The section we're on is factoring trig equations, but my basic factoring skills have gone all dry and I can't remember how to do it simply. If I knew how to factor these I could get the answers, so the factoring is mainly what I need help on--or if it's not factoring, then how to set it up so I can find all the angles within the equation.
    Last edited by augustfai; April 14th 2008 at 02:41 PM.
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  2. #2
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    1. 1-\sin(t) = \sqrt{3}\cos(t)

    (1-\sin(t))^2 = ( \sqrt{3}\cos(t))^2

    \sin^2(t) +2 \sin(t) +1 = 3\cos^2(t)

    \sin^2(t) +2 \sin(t) +1= 3(1-\sin^2(t))

    \sin^2(t) +2 \sin(t) +1+3\sin^2(t) -3= 0

    4\sin^2(t) +2 \sin(t) -2= 0

    2\sin^2(t) + \sin(t) -1= 0

    ( \sin(t) -1)(2 \sin(t) +1) = 0

    you could take it from here...


    2. \cos(x) - \sin(x) = 1

    ( \cos(x) - \sin(x))^2 = 1^2

     \cos^2(x) - 2\cos(x)\sin(x) + \sin^2(x) = 1

     1- \sin^2(x) - 2\cos(x)\sin(x) + \sin^2(x) = 1

     2\cos(x)\sin(x) =0

    you could take it from here...


    3. 2\tan(t) - \sec^2(t) = 0

    2\tan(t) - (1+\tan^2(t)) = 0

    2\tan(t) - 1-\tan^2(t)) = 0

    \tan(t)  = 1

    you could take it from here...


    4. \tan(x) + \sec(x) = 1

    (\tan(x) + \sec(x))^2 = 1^2

    \tan^2(x) + 2\tan(x)\sec(x) + \sec^2(x) = 1

    \tan^2(x) + 2\tan(x)\sec(x) + 1+\tan^2(x) = 1

    2\tan^2(x) + 2\tan(x)\sec(x) = 0

    2 \left( \frac{\sin^2(x)}{cos^2(x)} + \frac{\sin(x)}{\cos^2(x)} \right)= 0

    2 \left( \frac{\sin^2(x)+\sin(x)}{cos^2(x)} \right)= 0

    you could take it from here...


    5. \cot(a) + \tan(a) = \csc(a) \sec(a)

    \frac{\cos(a)}{\sin(a)} + \frac{\sin(a)}{\cos(a)} = \frac{1}{\sin(a)} \times \frac{1}{cos(a)}

    \frac{\cos^2(a)}{\sin(a)\cos(a)} + \frac{\sin^2(a)}{\cos(a)\sin(a)} = \frac{1}{\sin(a)\cos(a)}

    \frac{1}{\sin(a)\cos(a)}= \frac{1}{\sin(a)\cos(a)}

    you could take it from here...


    6.  \sec^5(x) = 4\sec(x)

     \sec^4(x) = 4

     \sec(x) = \sqrt[4]{4}

    you could take it from here...
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