............
then,
2/sin^2 x
Now I know that 1/sin^2 x= csc^2 x, so
2/sin^2 x=1/2 csc^2 x
NO...! Why are you inverting the 2 along with sin?
2/sin^2 x= 2 (1/sin^2 x) = 2 csc^2 x
...............
1/(1-cos x) +1/(1+cos x)=2 csc^2 x
After getting the common denominator-->
2/(1-cos^2 x)
then,
2/sin^2 x
Now I know that 1/sin^2 x= csc^2 x, so
2/sin^2 x=1/2 csc^2 x
But I need 2 csc^2 x.....
What do I need to do?
Thanks in advance.