1/(1-cos x) +1/(1+cos x)=2 csc^2 x

After getting the common denominator-->

2/(1-cos^2 x)

then,

2/sin^2 x

Now I know that 1/sin^2 x= csc^2 x, so

2/sin^2 x=1/2 csc^2 x

But I need 2 csc^2 x.....

What do I need to do?

Thanks in advance.

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- Apr 13th 2008, 03:08 PMbeetzProving trig identities
1/(1-cos x) +1/(1+cos x)=2 csc^2 x

After getting the common denominator-->

2/(1-cos^2 x)

then,

2/sin^2 x

Now I know that 1/sin^2 x= csc^2 x, so

2/sin^2 x=1/2 csc^2 x

But I need 2 csc^2 x.....

What do I need to do?

Thanks in advance. - Apr 13th 2008, 03:15 PMIsomorphism
............

then,

2/sin^2 x

Now I know that 1/sin^2 x= csc^2 x, so

2/sin^2 x=1/2 csc^2 x

NO...! Why are you inverting the 2 along with sin?

2/sin^2 x= 2 (1/sin^2 x) = 2 csc^2 x

............... - Apr 13th 2008, 03:21 PMbeetz
omg. I don't know why I did that! I guess my brain function is ailing after doing 55 of these.

Thanks so much!