what is the exact value of
sin^2(pie/6) - 2sin(pie/6)cos(pie/6) + cos^2(-pie/6)
a. 2- (squareroot)3
b. (2- (squareroot)3)/2
c. (2+ (squareroot)3/2
d. 2+ (squareroot)3
Please use LaTeX to enter math equations. You can learn how here:
http://www.mathhelpforum.com/math-he...read.php?t=266
You can also click on the equation that I wrote and see the code I used to generate it.
The above would look like this:
$\displaystyle \sin^2(\frac{\Pi}{2}) - 2\sin(\frac{\Pi}{6}) + \cos^2(\frac{-\Pi}{6})$
a. $\displaystyle 2 - \sqrt {3} $
b. $\displaystyle \frac {2 - \sqrt {3}}{2} $
c. $\displaystyle 2 + \sqrt {3} $
LaTeX is also case sensitive. Therefore, big $\displaystyle \Pi$ and small $\displaystyle \pi$ mean and display differently.
$\displaystyle \left (\sin(\frac{\pi}{6})\right )^{2}-2\,\sin(\frac{\pi}{6})\cos(\frac{\pi}{6})+
\left (\cos(\frac{\pi}{6})\right )^{2}$
$\displaystyle = \left (\sin(\frac{\pi}{6})-\cos(\frac{\pi}{6})\right )^{2} $
$\displaystyle = 1-\frac{1}{2}\,\sqrt {3}$