what is the exact value of

sin^2(pie/6) - 2sin(pie/6)cos(pie/6) + cos^2(-pie/6)

a. 2- (squareroot)3

b. (2- (squareroot)3)/2

c. (2+ (squareroot)3/2

d. 2+ (squareroot)3

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- May 26th 2005, 08:42 PMkelseyexact values
what is the exact value of

sin^2(pie/6) - 2sin(pie/6)cos(pie/6) + cos^2(-pie/6)

a. 2- (squareroot)3

b. (2- (squareroot)3)/2

c. (2+ (squareroot)3/2

d. 2+ (squareroot)3 - May 26th 2005, 09:25 PMMathMan
Please use LaTeX to enter math equations. You can learn how here:

http://www.mathhelpforum.com/math-he...read.php?t=266

You can also click on the equation that I wrote and see the code I used to generate it.

The above would look like this:

$\displaystyle \sin^2(\frac{\Pi}{2}) - 2\sin(\frac{\Pi}{6}) + \cos^2(\frac{-\Pi}{6})$

a. $\displaystyle 2 - \sqrt {3} $

b. $\displaystyle \frac {2 - \sqrt {3}}{2} $

c. $\displaystyle 2 + \sqrt {3} $ - May 26th 2005, 11:00 PMpaultwang
LaTeX is also case sensitive. Therefore, big $\displaystyle \Pi$ and small $\displaystyle \pi$ mean and display differently.

$\displaystyle \left (\sin(\frac{\pi}{6})\right )^{2}-2\,\sin(\frac{\pi}{6})\cos(\frac{\pi}{6})+

\left (\cos(\frac{\pi}{6})\right )^{2}$

$\displaystyle = \left (\sin(\frac{\pi}{6})-\cos(\frac{\pi}{6})\right )^{2} $

$\displaystyle = 1-\frac{1}{2}\,\sqrt {3}$ - May 27th 2005, 07:27 AMMathManQuote:

Originally Posted by**paultwang**

- May 28th 2005, 09:39 AMkelseythanks
but can you help me with the queston now?

- May 29th 2005, 08:25 AMpaultwang
I gave you enough hints.