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Math Help - Trigonomic Functions (Check My Solution)

  1. #1
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    Question Trigonomic Functions (Check My Solution)

    1. Find the amplitude, period, and phase shift of the function.

    y=3cos(2x+pi)

    What I think it should be:
    amplitude=3
    period= pi
    phase shift=2

    2. Write the equation of sine that has the given characteristics:
    amplitude=3
    period= pi/2
    phase shift=2

    What I think it should be:
    y=3sin[3(x-2)]
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    You tell me if you are right

    Quote Originally Posted by wickwiki View Post
    1. Find the amplitude, period, and phase shift of the function.

    y=3cos(2x+pi)

    What I think it should be:
    amplitude=3
    period= pi
    phase shift=2

    2. Write the equation of sine that has the given characteristics:
    amplitude=3
    period= pi/2
    phase shift=2

    What I think it should be:
    y=3sin[3(x-2)]
    in the equation y=acos(bx+c)....the amplitude is |a|...the period is \frac{2\pi}{|b|} and the phase shift is \frac{-c}{b}...so are you right?
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  3. #3
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    in the equation ....the amplitude is ...the period is and the phase shift is ...so are you right?
    1.


    So, this would be:
    amplitude=3
    period= 2pi/2
    phase shift= -pi/2


    2. Write the equation of sine that has the given characteristics:
    amplitude=3
    period=
    phase shift=2

    What I think it should be:
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Ok but look

    Quote Originally Posted by wickwiki View Post
    1.


    So, this would be:
    amplitude=3
    period= 2pi/2
    phase shift= -pi/2


    2. Write the equation of sine that has the given characteristics:
    amplitude=3
    period=
    phase shift=2

    What I think it should be:
    if 3sin(3x-6) was the answer...using the method I gave you...the amplitude is |3|...check...the period \frac{2\pi}{|3|}.. =(....and its phase shift \frac{-(-6)}{3}=2...=)...try 3sin(4x-8)
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