# Thread: Trigonomic Functions (Check My Solution)

1. ## Trigonomic Functions (Check My Solution)

1. Find the amplitude, period, and phase shift of the function.

$\displaystyle y=3cos(2x+pi)$

What I think it should be:
amplitude=3
period=$\displaystyle pi$
phase shift=2

2. Write the equation of sine that has the given characteristics:
amplitude=3
period=$\displaystyle pi/2$
phase shift=2

What I think it should be:
$\displaystyle y=3sin[3(x-2)]$

2. ## You tell me if you are right

Originally Posted by wickwiki
1. Find the amplitude, period, and phase shift of the function.

$\displaystyle y=3cos(2x+pi)$

What I think it should be:
amplitude=3
period=$\displaystyle pi$
phase shift=2

2. Write the equation of sine that has the given characteristics:
amplitude=3
period=$\displaystyle pi/2$
phase shift=2

What I think it should be:
$\displaystyle y=3sin[3(x-2)]$
in the equation $\displaystyle y=acos(bx+c)$....the amplitude is $\displaystyle |a|$...the period is $\displaystyle \frac{2\pi}{|b|}$ and the phase shift is $\displaystyle \frac{-c}{b}$...so are you right?

3. in the equation ....the amplitude is ...the period is and the phase shift is ...so are you right?
1.

So, this would be:
amplitude=3
period=$\displaystyle 2pi/2$
phase shift= $\displaystyle -pi/2$

2. Write the equation of sine that has the given characteristics:
amplitude=3
period=
phase shift=2

What I think it should be:

4. ## Ok but look

Originally Posted by wickwiki
1.

So, this would be:
amplitude=3
period=$\displaystyle 2pi/2$
phase shift= $\displaystyle -pi/2$

2. Write the equation of sine that has the given characteristics:
amplitude=3
period=
phase shift=2

What I think it should be:
if $\displaystyle 3sin(3x-6)$ was the answer...using the method I gave you...the amplitude is $\displaystyle |3|$...check...the period $\displaystyle \frac{2\pi}{|3|}$.. =(....and its phase shift $\displaystyle \frac{-(-6)}{3}=2$...=)...try $\displaystyle 3sin(4x-8)$