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Math Help - trig identity

  1. #1
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    trig identity

    sin(t+s)sin(t-s)=sin^2t-sin^2s
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    here is a long-winded reason

    Quote Originally Posted by Thelema View Post
    sin(t+s)sin(t-s)=sin^2t-sin^2s
    if you use your identitys you cansee that we have [sin(t)cos(s)+sin(s)cost(t)][sin(t)cos(s)-sin(s)cos(t)] I think you can see where to go fomr there
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