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sin(t+s)sin(t-s)=sin^2t-sin^2s

Quote: Originally Posted by Thelema sin(t+s)sin(t-s)=sin^2t-sin^2s if you use your identitys you cansee that we have $\displaystyle [sin(t)cos(s)+sin(s)cost(t)][sin(t)cos(s)-sin(s)cos(t)]$ I think you can see where to go fomr there