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  1. #1
    Newbie veronica mars's Avatar
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    just checking

    ok i finished the problem but i want 2 know what u got...

    the sides of a parallelogram are 4.0cm and 6.0cm. One angle is 58 degrees while another is 122 degrees. Find the lengths of the diagonals of the parallelogram.

    I got one diagonal as 5.2 and the other as 8.8
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    The

    Quote Originally Posted by veronica mars View Post
    ok i finished the problem but i want 2 know what u got...

    the sides of a parallelogram are 4.0cm and 6.0cm. One angle is 58 degrees while another is 122 degrees. Find the lengths of the diagonals of the parallelogram.

    I got one diagonal as 5.2 and the other as 8.8
    answer should be 7.211...did you figure out it was a right triangle?
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  3. #3
    Newbie veronica mars's Avatar
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    no....

    Quote Originally Posted by Mathstud28 View Post
    answer should be 7.211...did you figure out it was a right triangle?
    i just did the formula u gave me for the other problem with the two angles to find the lengths of the diagonals
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Yes

    Quote Originally Posted by veronica mars View Post
    i just did the formula u gave me for the other problem with the two angles to find the lengths of the diagonals
    but did you realize that the $\displaystyle \theta$ we are using in this case is $\displaystyle 180-\frac{122}{2}-\frac{58}{2}=90$ in which case the formula I gave you reverts back to the pythagorean theorem since the $\displaystyle cos(90)=0$ elminating the last term
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  5. #5
    Newbie veronica mars's Avatar
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    Quote Originally Posted by Mathstud28 View Post
    but did you realize that the $\displaystyle \theta$ we are using in this case is $\displaystyle 180-\frac{122}{2}-\frac{58}{2}=90$ in which case the formula I gave you reverts back to the pythagorean theorem since the $\displaystyle cos(90)=0$ elminating the last term
    no. now i am even more confused than i already was, but its ok. im getting this whole assignment wrong anyways its the beginning of the quarter. i will be able to bounce back.
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