# just checking

• Apr 7th 2008, 05:12 PM
veronica mars
just checking
ok i finished the problem but i want 2 know what u got...

the sides of a parallelogram are 4.0cm and 6.0cm. One angle is 58 degrees while another is 122 degrees. Find the lengths of the diagonals of the parallelogram.

I got one diagonal as 5.2 and the other as 8.8
• Apr 7th 2008, 05:18 PM
Mathstud28
The
Quote:

Originally Posted by veronica mars
ok i finished the problem but i want 2 know what u got...

the sides of a parallelogram are 4.0cm and 6.0cm. One angle is 58 degrees while another is 122 degrees. Find the lengths of the diagonals of the parallelogram.

I got one diagonal as 5.2 and the other as 8.8

answer should be 7.211...did you figure out it was a right triangle?
• Apr 7th 2008, 05:28 PM
veronica mars
no....
Quote:

Originally Posted by Mathstud28
answer should be 7.211...did you figure out it was a right triangle?

i just did the formula u gave me for the other problem with the two angles to find the lengths of the diagonals
• Apr 7th 2008, 05:59 PM
Mathstud28
Yes
Quote:

Originally Posted by veronica mars
i just did the formula u gave me for the other problem with the two angles to find the lengths of the diagonals

but did you realize that the $\theta$ we are using in this case is $180-\frac{122}{2}-\frac{58}{2}=90$ in which case the formula I gave you reverts back to the pythagorean theorem since the $cos(90)=0$ elminating the last term
• Apr 7th 2008, 06:17 PM
veronica mars
Quote:

Originally Posted by Mathstud28
but did you realize that the $\theta$ we are using in this case is $180-\frac{122}{2}-\frac{58}{2}=90$ in which case the formula I gave you reverts back to the pythagorean theorem since the $cos(90)=0$ elminating the last term

no. now i am even more confused than i already was, but its ok. im getting this whole assignment wrong anyways :( its the beginning of the quarter. i will be able to bounce back.