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Math Help - proving trig identities

  1. #1
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    proving trig identities

    i need some help with this identity


    (sinx+tanx)/1+secx=sinx
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  2. #2
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    (sinx+tanx)/1+secx=sinx

    First, the numerator:
    (sinx+tanx) = (sinx + sinx/cosx) = (sinx) (1+(1/cosx)) = (sinx) (1+secx)


    The denominator (of the left side of equation) is (1+secx)
    The (1+secx) on the top and the (1+sec x) on the bottom cancel out.

    You are left with sinx = sinx.

    -Andy
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