solve for Θ using the interval 0≤Θ≤360
2cos^2 Θ+sinΘ=1
The number of degrees in the smallest positive angle that satisfies the equation
3cos2x+2 sin x+1=0
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solve for Θ using the interval 0≤Θ≤360
2cos^2 Θ+sinΘ=1
The number of degrees in the smallest positive angle that satisfies the equation
3cos2x+2 sin x+1=0
Factor and solve forand then
Again factor and solve.