Show that equation 3tanѲ = 2cosѲ

may be written as 2sinēѲ + 3sinѲ - 2 = 0

thanks

i think i started it:

3tanѲ = 2cosѲ

3sinѲ/cosѲ = 2(1-sinѲ)

3sinѲ/cosѲ = 2 - 2sinѲ

now i'm stuck

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- Apr 6th 2008, 09:49 AM #1

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- Apr 6th 2008, 09:52 AM #2

- Apr 6th 2008, 09:54 AM #3

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$\displaystyle \frac{3sin x}{\cos x} = 2 \cos x$

multiply by cosx

$\displaystyle 3sin x = 2 \cos^2 x$

$\displaystyle 3sin x = 2 (1- \sin^2 x)$

... continue

Bobak

Edit: Jhevon beat me, gosh i wish there was a feature saying who is reply while your typing.

- Apr 6th 2008, 10:07 AM #4