Show that equation 3tanѲ = 2cosѲ may be written as 2sinēѲ + 3sinѲ - 2 = 0 thanks i think i started it: 3tanѲ = 2cosѲ 3sinѲ/cosѲ = 2(1-sinѲ) 3sinѲ/cosѲ = 2 - 2sinѲ now i'm stuck

Follow Math Help Forum on Facebook and Google+

Originally Posted by gracey Show that equation 3tanѲ = 2cosѲ may be written as 2sinēѲ + 3sinѲ - 2 = 0 thanks i think i started it: 3tanѲ = 2cosѲ 3sinѲ/cosѲ = 2(1-sinѲ) 3sinѲ/cosѲ = 2 - 2sinѲ now i'm stuck cos x is NOT equal to 1 - sin x. learn your identities. when you get to the 3sin(x)/cos(x) = 2cos(x) line, multiply through by cos(x), then replace (cos(x))^2 with 1 - (sin(x))^2 and the rest is routine

multiply by cosx ... continue Bobak Edit: Jhevon beat me, gosh i wish there was a feature saying who is reply while your typing.

Originally Posted by bobak gosh i wish there was a feature saying who is reply while your typing. i asked about that once upon a time, it seems everyone has forgotten about it i'll bring up the issue with the administrators again. *yawn* ...later ...

View Tag Cloud