Given that $\displaystyle x$ takes a value near $\displaystyle \frac{\pi}{2}$, explain why $\displaystyle cosx = \frac{\pi}{2}-x$
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Hello, cos(x)=sin(pi/2-x) pi/2-x is near 0, because x is near pi/2 We know that sin(y) ~ y when y is near 0. Hence cos(x) ~ pi/2-x
Last edited by Moo; Apr 5th 2008 at 07:24 AM.
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