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Math Help - tis oso!! HELP

  1. #1
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    tis oso!! HELP

    explain plz..
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  2. #2
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    You want answers to all of these?!?! Cmon now. At least try. Is there one in particular you need help on?
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  3. #3
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    but i realli dunno!? my test i get 10/60 lei ?! if i no i would not hv fail so badly
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  4. #4
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    12,

    \sin x=\frac{\mbox{opposite}}{\mbox{hypotenuse}}=\frac{  5}{8}
    Therefore,
    x=\sin^{-1}(5/8)\approx 38.9^o

    \tan 40^o=\frac{\mbox{opposite}}{\mbox{adjacent}}=\frac  {PQ}{5}
    Thus, solve for PQ, by mutiplying by five both sides,
    PQ=5\tan 40^o=\approx 4.2

    \cos y=\frac{\mbox{adjacent}}{\mbox{hypotenuse}}=\frac{  8}{13}
    Therefore,
    y=\cos^{-1} (8/13)\approx 52.0^o
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  5. #5
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    thxz.. i just dunno how to use all the formulas.. the toa cah soh and sin rule. cos rule all tis..
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