Long time no see. This is actually for my roomate and we have not been able to solve this problem
Secant X = CosineX + SinX x TangentX
Any help is appreciated
Nm thanks
Long time no see. This is actually for my roomate and we have not been able to solve this problem
Secant X = CosineX + SinX x TangentX
Any help is appreciated
Nm thanks
$\displaystyle sec(x)=cos(x)+sin(x)tan(x)$
Let's turn the right into the left:
$\displaystyle cos(x)+sin(x)\cdot\frac{sin(x)}{cos(x)}$
$\displaystyle cos(x)+\frac{sin^{2}(x)}{cos(x)}$
$\displaystyle \frac{cos^{2}(x)+sin^{2}(x)}{cos(x)}$
As you should know, the numerator is equal to 1 and we have:
$\displaystyle \frac{1}{cos(x)}=sec(x)$
$\displaystyle csc(x)-sin(x)=\frac{cot(x)}{sec(x)}$
$\displaystyle \frac{1}{sin(x)}-sin(x)=\frac{\frac{cos(x)}{sin(x)}}{\frac{1}{cos(x )}}$
$\displaystyle \frac{1-sin^{2}(x)}{sin(x)}=\frac{cos^{2}(x)}{sin(x)}$
$\displaystyle \frac{cos^{2}(x)}{sin(x)}=\frac{cos^{2}(x)}{sin(x) }$