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Math Help - Finding Missing Triangle Lengths...

  1. #16
    Member Danshader's Avatar
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    well the area formula for a triangle is always:

    (1/2)(height)(base length)

    in your case it is
    (1/2)(sqrt(108))(12)
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  2. #17
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    how do you enter that into a calculator? (graphing)
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  3. #18
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    enter what? o.o?
    (1/2)(sqrt(108))(12)?

    first you calculate square root of 108 then multiply by 12 then by 1/2
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  4. #19
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    what does that round to..
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  5. #20
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    well i get the area = 62.35382907
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  6. #21
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    So can I?

    Can I leave it in:

    A = 1/2(√108)(12)
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  7. #22
    Member Danshader's Avatar
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    yeah sure no harm in it. it is tidier to leave it in that form.
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  8. #23
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    The Second Pic I sent!

    Hey on the second pic I attached...I got this for the area..

    1093.5 = 4.5 times 243...
    Attached Thumbnails Attached Thumbnails Finding Missing Triangle Lengths...-photo-81.jpg  
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  9. #24
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    lol xD you got it wrong.

    you forgot to square root 243 and it is not multiplied with 4.5 but 18(0.5)

    your working should be as below:

    (x+y)^2 = 18^2 - 9^2
    (x+y) = sqrt(243)

    area = (1/2)(base length)(height)
    = (1/2)(18)(sqrt(243))
    = 140.2961154
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  10. #25
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    Exclamation Wait

    I thought that √243 times √243 is 243...
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  11. #26
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    no o.o" your height is sqrt(243) but your base length is 18 (length of one side of the triangle)
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  12. #27
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    Post So..

    4.5 times the square root of 243

    take whatever that answer is and times it by two..
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  13. #28
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    ic you are using the area of 2 triangles .. yup thats absolutely correct.
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  14. #29
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    Check this out

    I got an area of 72..because: 6 divided by 2 equals 3. times 12. equals 36. times that by 2..(two triangles) you get 72.
    Attached Thumbnails Attached Thumbnails Finding Missing Triangle Lengths...-photo-90.jpg  
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  15. #30
    Member Danshader's Avatar
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    er where did you get your 6 from? dividing it with 2 and multiplying it with 12 is correct but 6 is not correct.

    or if you area taking 6 as the base then 12 is not correct
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