Thread: Finding Missing Triangle Lengths...

well the area formula for a triangle is always:

(1/2)(height)(base length)

in your case it is
(1/2)(sqrt(108))(12)

how do you enter that into a calculator? (graphing)

enter what? o.o?
(1/2)(sqrt(108))(12)?

first you calculate square root of 108 then multiply by 12 then by 1/2

what does that round to..

well i get the area = 62.35382907

Can I leave it in:

A = 1/2(√108)(12)

yeah sure no harm in it. it is tidier to leave it in that form.

Hey on the second pic I attached...I got this for the area..

1093.5 = 4.5 times 243...

lol xD you got it wrong.

you forgot to square root 243 and it is not multiplied with 4.5 but 18(0.5)

your working should be as below:

(x+y)^2 = 18^2 - 9^2
(x+y) = sqrt(243)

area = (1/2)(base length)(height)
= (1/2)(18)(sqrt(243))
= 140.2961154

I thought that √243 times √243 is 243...

no o.o" your height is sqrt(243) but your base length is 18 (length of one side of the triangle)

4.5 times the square root of 243

take whatever that answer is and times it by two..

ic you are using the area of 2 triangles .. yup thats absolutely correct.

I got an area of 72..because: 6 divided by 2 equals 3. times 12. equals 36. times that by 2..(two triangles) you get 72.

er where did you get your 6 from? dividing it with 2 and multiplying it with 12 is correct but 6 is not correct.

or if you area taking 6 as the base then 12 is not correct