Results 1 to 3 of 3

Math Help - need homework help-trig

  1. #1
    Newbie
    Joined
    Mar 2008
    Posts
    6

    need homework help-trig

    I need to simplify these equations:

    (1-cosx)(1+secx)cosx

    tanx+cotx/sec^2x

    (tan^2x/secx+1)+1

    And for these, I need to solve for the degrees (nearest tenth)

    tan^2x=1

    2tan^2x=3tanx-1

    Solve for radians (nearest hundreth)

    3sinx=cosx

    secx=2cscx


    Any help is greatly appreciated!!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,689
    Thanks
    617
    Hello, legolewinsky!

    Here are the first few . . .


    (1-\cos x)(1+\sec x)\,\cos x
    We have: . (1 - \cos x)\underbrace{\cos x\left(1 + \frac{1}{\cos x}\right)}

    . . . . . . = \quad(1-\cos x)\quad(\cos x + 1) \;\;=\;\;1-\cos^2\!x \;\;=\;\;\sin^2\!x




    \frac{\tan x+\cot x}{\sec^2\!x}
    We have: . \frac{\tan x + \dfrac{1}{\tan x}}{\sec^2\!x} \;\;=\;\;\frac{\dfrac{\overbrace{\tan^2\!x+1}^{\te  xt{This is }sec^2\!x}}{\tan x}}{\sec^2\!x} \;\;=\;\;\frac{\dfrac{\sec^2\!x}{\tan x}}{\sec^2\!x} \;\;=\;\;\frac{1}{\tan  x}\;\;=\;\;\cot x



    \frac{\tan^2\!x}{\sec x+1}+1
    Since \tan^2\!x \:=\:\sec^2\!x-1, we have: . \frac{\sec^2\!x - 1}{\sec x + 1} + 1

    Factor and reduce: . \frac{(\sec x - 1)(\sec x + 1)}{\sec x + 1} + 1 \;\;=\;\;(\sec x - 1) +1 \;\;=\;\;\sec x

    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2008
    Posts
    6

    thanks

    Thank you so much!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Help with Trig. homework please
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: January 24th 2010, 12:25 PM
  2. Trig homework
    Posted in the Trigonometry Forum
    Replies: 0
    Last Post: December 1st 2008, 09:21 AM
  3. Trig homework
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: December 1st 2008, 03:41 AM
  4. trig homework
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: August 8th 2008, 08:09 AM
  5. Trig/cal homework help
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: March 22nd 2007, 03:09 PM

Search Tags


/mathhelpforum @mathhelpforum