Thread: i have problem in trigo general solution again

p213 q29 b

sorry for my laziness. i posted my question as a scanned handwriting image for a long time and i thought it was acceptable by helpers cos i got replies everytime ...

Please type your questions. I don't think anyone will want to help you this way.

Originally Posted by wingless

Please type your questions. I don't think anyone will want to help you this way.

This is his work, huh ?

Originally Posted by Moo

This is his work, huh ?

He posted a scanned large image of handwriting which was hard to read. He typed it and it's better now

But I still don't have an idea how to solve this.. My trig is not good ;P

Ok, i remember, i thought it was another question ^^

For the problem : there's something disturbing me : the condition of applying the formula is that tan(x)=tan(x+a)

If you take a=pi/3, tan(x) is not = to tan(x+pi/3)



(i wonder how you typed it...)

Originally Posted by afeasfaerw23231233

p213 q29 b
Attachment 5492
sorry for my laziness. i posted my question as a scanned handwriting image for a long time and i thought it was acceptable by helpers cos i got replies everytime ...

in the first line

"given: ...."

there's a typo. The first = obviously should be a multiplication.

Your answer and the books answer do NOT appear to be exactly equivalent. Your answer looks more correct. The book appears less correct. This is the problem when part of the answer has been rounded to a certain decimal approximation (in the case of the book, 1 decimal place) ....

oh no, sorry! i
i make a typo mistake. It should be tan x tan (x +a )= k

Originally Posted by afeasfaerw23231233

oh no, sorry! i
i make a typo mistake. It should be tan x tan (x +a )= k

That's OK . I easily realised what it was meant to be.