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Math Help - problem in general solution

  1. #1
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    problem in general solution

    problem in general solutionproblem in general solution-out0088.jpeg
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by afeasfaerw23231233 View Post
    problem in general solutionClick image for larger version. 

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    If I am reading them correctly any of these are good.

    Note that 2n \pm 1 is just a way to denote an arbitrary odd number. So you could simplify this by using
    (2n + 1)\pi \pm y
    and still cover all of your solutions.

    -Dan
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  3. #3
    Behold, the power of SARDINES!
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    This may help.

    I messed this up. I will try again.
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  4. #4
    Behold, the power of SARDINES!
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    Maybe i'm wrong but

     \cos(x \pm y)=\cos(x) \cos(y) \mp \sin(x) \sin(y)

    How do you make the connection?
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by TheEmptySet View Post
    Maybe i'm wrong but

     \cos(x \pm y)=\cos(x) \cos(y) \mp \sin(x) \sin(y)

    How do you make the connection?
    I believe it is meant to read:
    -cos(y) = cos(\pi \pm y)
    which is correct.

    -Dan
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