Math Help - problem in general solution

1. problem in general solution

problem in general solution

2. Originally Posted by afeasfaerw23231233
problem in general solution
If I am reading them correctly any of these are good.

Note that $2n \pm 1$ is just a way to denote an arbitrary odd number. So you could simplify this by using
$(2n + 1)\pi \pm y$
and still cover all of your solutions.

-Dan

3. This may help.

I messed this up. I will try again.

4. Maybe i'm wrong but

$\cos(x \pm y)=\cos(x) \cos(y) \mp \sin(x) \sin(y)$

How do you make the connection?

5. Originally Posted by TheEmptySet
Maybe i'm wrong but

$\cos(x \pm y)=\cos(x) \cos(y) \mp \sin(x) \sin(y)$

How do you make the connection?
I believe it is meant to read:
$-cos(y) = cos(\pi \pm y)$
which is correct.

-Dan