Let f(x)=1-tan^2x and g(x)=tanx. Find the value of x in the interval (0, pie/2) where f(x)=g(x) Can anyone help me with this question?
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You can see that you can solve it as if it were a quadratic equation. Just make sure your solution for x is in the solution set provided. Edit: Just to make it easier to visualize, let y = tan x. So you have . So: etc.
Originally Posted by lemontea Let f(x)=1-tan^2x and g(x)=tanx. Find the value of x in the interval (0, pie/2) where f(x)=g(x) Can anyone help me with this question? we get.. by the quadratic formula we get.. You should be able to finish from here. Good luck.
the answer i got is y=-1+squareroot 5/2 or y=-1-squareroot 5/2 am i right?
Yes. So:
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