two tricky trig problems
Show All Work Please
1) solve: cos2x-cos6x=0
2) The number of hours daylight in Detroit on day 't' ( with t = 0 on January 1st) of a non-leap year is given by:
a) What days have exactly 11 hrs. of daylight
b)What day has a maximum amount of daylight
if you thought those were easy try
Solve: X (to the 3/8) - (square root of negative one)(square root of 3)=3
=> cos(2x) = cos(6x).
Originally Posted by rutheada000
Note that the general solution to cos(A) = cos(B) is:
A = B + 2 n pi and A = -B + 2 n pi
where n is an integer .....