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Math Help - more angle of refraction.

  1. #1
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    more angle of refraction.

    The drawing shows a rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 36.0 angle of incidence. At what angle of refraction does the ray leave the glass at point B?

    Please explain a way to reach the solution for this problem. I tried using the equation: n2*sin(36) / n1

    pic: http://img128.imageshack.us/img128/900/13113445ga1.png

    it does not seem to work with the problems i'm working with. I may not be using the equation correctly.
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  2. #2
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    Quote Originally Posted by rcmango View Post
    The drawing shows a rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 36.0 angle of incidence. At what angle of refraction does the ray leave the glass at point B?

    Please explain a way to reach the solution for this problem. I tried using the equation: n2*sin(36) / n1

    pic: http://img128.imageshack.us/img128/900/13113445ga1.png

    it does not seem to work with the problems i'm working with. I may not be using the equation correctly.
    Probably you are only a little bit confused because you use 2 different types of media.

    The CS_2 is the first (surrounding) medium, the glass is the second one. Then the law of Snellius states:

    \frac{\sin(\alpha)}{\sin(\beta)} = \frac{n_2}{n_1}

    You want to get \beta :

    \sin(\beta) = \frac{n_1}{n_2} \cdot \sin(\alpha)~\implies~ \sin(\beta) = \frac{1.63}{1.52} \cdot \sin(36^\circ)~\implies~\beta \approx 39.1^\circ

    That means the angle of refraction is greater than the angle of incidence.
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  3. #3
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    Okay, i'm following you,

    Is, 39.1 the angle of refraction that exits the glass for part A?

    so now need to find for part B??
    Last edited by rcmango; March 3rd 2008 at 12:58 PM.
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