A ray of light impinges from air onto a block of ice (n = 1.309) at a 63.0° angle of incidence. Assuming that this angle remains the same, find the difference 2, ice - 2, water in the angles of refraction when the ice turns to water (n = 1.333).
theta2 ice - theta2, water
I have tried using this formula n1* sin(63) / n2
and then using n2*sin(63) / n1
then i subtract the theta and used inverse sin to get an answer.
I have 1.85 degrees which isn't correct.
anyone who can correct me on this one please.