Could you word that better... It's hard to understand what you're asking.
I think it's just asking to find this difference:
Maybe that's correct?
A ray of light impinges from air onto a block of ice (n = 1.309) at a 63.0° angle of incidence. Assuming that this angle remains the same, find the difference 2, ice - 2, water in the angles of refraction when the ice turns to water (n = 1.333).
theta2 ice - theta2, water
I have tried using this formula n1* sin(63) / n2
and then using n2*sin(63) / n1
then i subtract the theta and used inverse sin to get an answer.
I have 1.85 degrees which isn't correct.
anyone who can correct me on this one please.
no, unfortunately, I also tried using that formula without dividing by n1 or n2 and that wasn't correct either.
I need to try and find the angle of refraction from the difference of ice and water. ice - water.
still haven't reached the answer for this one.
Here's my guess: You need to find the angle of refraction using the ice, then subtract from that the angle of refraction using the water?
If that's true then Aryth's answer is correct. (Assuming he did the math correctly, I didn't check the numbers.)