Find the general solution of:
5cot(3x + 4) = 1
Thus,Originally Posted by LilDragonfly
$\displaystyle \cot (3x+4)=\frac{1}{5}$
Let,
$\displaystyle y=3x+4$
Then,
$\displaystyle \cot y=\frac{1}{5}$
which you find that,
$\displaystyle y=\cot^{-1}(1/5)+\pi k$
Thus,
$\displaystyle 3x+4=\cot^{-1}(1/5)+\pi k$
Thus,
$\displaystyle x=\frac{1}{3}\cot^{-1}(1/5)+\frac{\pi k}{3}-4$