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Math Help - analytic trig

  1. #1
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    analytic trig



    yeah i dont understand. why there are no solutions?

    greater than 0??
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by algebra2 View Post


    yeah i dont understand. why there are no solutions?

    greater than 0??
    do you realize that \sin^2 x is always non-negative? it's a square term, so it is greater than or equal to zero (it is also less than or equal to 1, to be precise)

    2 \sin^2 x + 1 = 0

    means 2 \sin^2 x = -1

    but -1 is negative, thus we cannot solve this for any real number x

    got it?
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  3. #3
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    yea thanks. i kind of overlooked that i guess.
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