Find the value of if and I'm not exactly sure how to type the degrees sign using latex. And I'm also lost on how to tackle this problem.
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Originally Posted by TI-84 Find the value of if and I'm not exactly sure how to type the degrees sign using latex. And I'm also lost on how to tackle this problem. Double angle formula: . Let : . You know where ..... from this you can get . Substitute the value of into the above formula and use the fact that to justify using the positive root. Capisce?
How exactly do I know what the value of is?
Originally Posted by TI-84 How exactly do I know what the value of is? Substitute into . Solve for and hence get . Use the given fact that and hence to justify keeping the negative value for .
Originally Posted by mr fantastic Substitute into . Solve for and hence get . Use the given fact that and hence to justify keeping the negative value for . Alright so what I'm getting from what you said is Which in turn gives I'm pretty sure I screwed up. Its some tricky stuff.
Originally Posted by TI-84 Alright so what I'm getting from what you said is Which in turn gives I'm pretty sure I screwed up. Its some tricky stuff. Since you have to plug in only the value (without the tan-function!). Your equation then becomes: Now go on!
I got Is that right? If it is do I follow that up by
Originally Posted by TI-84 I got Is that right? If it is do I follow that up by Originally Posted by mr fantastic Double angle formula: . Let : . You know where ..... from this you can get . Substitute the value of into the above formula and use the fact that to justify using the positive root. Capisce? Originally Posted by mr fantastic Substitute into . Mr F says: So . Solve for and hence get . Mr F says: So . Use the given fact that and hence to justify keeping the negative value for . Mr F says: So . Therefore . But . Therefore .
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