can show mi the step...thanx
if sin x=-0.6 and tan x = -0.75,then sec x is
1)-1.25
2)1.25
3)0.80
4)-1.35
Hello,Originally Posted by cheesepie
1. You know that $\displaystyle \tan(x)=\frac{\sin(x)}{\cos(x)}$ and
$\displaystyle \sec(x)=\frac{1}{\cos(x)}$ so
$\displaystyle \sec(x)=\frac{\tan(x)}{\sin(x)}$
Therefore: $\displaystyle \frac{-\frac{3}{4}}{-\frac{3}{5}}=\frac{5}{4}$
Thus the answer is 2)
Greetings
EB
Hello,Originally Posted by cheesepie
This problem is a tricky one, because you didn't give a value for tan(x). To be able to calculate a value I take the value from the previous problem: tan(x)=-.75
1. You know that $\displaystyle \cot(x)={\cos(x) \over \sin(x)}$ and
$\displaystyle \csc(x)={1 \over \sin(x)}$ and $\displaystyle \tan(x)={\sin(x) \over \cos(x)}$ So you get:
$\displaystyle \csc(x)={{\cos(x) \over \sin(x)} \over \cos(x)}}$ = $\displaystyle {{1 \over \tan(x)} \over \cos(x)}}$ = $\displaystyle {{1 \over -.75} \over .6}}$ = $\displaystyle -{20 \over 9} \approx -2.22$
This answer doesn't exist. So I presume, that my asumption about the value of tan(x) was incorrect. But maybe you can use my explanations when you plug in the right value for tan(x).
Greetings
EB