1. Simplify the expression

Simplify the given expression. The result will be one of $sin\; x, \;cos\; x,\; tan\; x,\; cot\; x,\; sec\; x,\; or\; csc\; x.$

$\frac{Tan\;x\;+\;Cot\;x}{Csc\;x}$

The answer to this one is $Sec\;x.$ I'm kinda confused on how they got it because I ended up with $Cos\;x$

2. Originally Posted by OzzMan
Simplify the given expression. The result will be one of $sin\; x, \;cos\; x,\; tan\; x,\; cot\; x,\; sec\; x,\; or\; csc\; x.$

$\frac{Tan\;x\;+\;Cot\;x}{Csc\;x}$

The answer to this one is $Sec\;x.$ I'm kinda confused on how they got it because I ended up with $Cos\;x$
Note: $\frac {\tan x + \cot x}{\csc x} = \sin x (\tan x + cot x)$

csc(x) = 1/sin(x)

i suppose you did something like csc(x) = 1/cos(x). happens all the time

3. Could you help me out with simplifying it? I'm kinda stuck. Can't seem to get Sec x as my answer.

4. Originally Posted by OzzMan
Could you help me out with simplifying it? I'm kinda stuck. Can't seem to get Sec x as my answer.
$\sin x (\tan x + \cot x) = \sin x \tan x + \sin x \cot x = \sin x \cdot \frac {\sin x}{\cos x} + \sin x \cdot \frac {\cos x}{\sin x}$

now simplify the fractions, combine them and continue

5. Thanks. Very long problem, but I got the right answer.