Algebraic Expressions in Trig.

**Godfather** · February 24th 2008, 08:10 AM

Find an algebraic expression equivalent to tan ( arc cos X )

Evaluate:
arc cos ( cos pi/3)
arc cos ( cos -pi/7)

**TheEmptySet** · February 24th 2008, 08:57 AM

Originally Posted by Godfather

Find an algebraic expression equivalent to tan ( arc cos X )

Evaluate:
arc cos ( cos pi/3)
arc cos ( cos -pi/7)

Draw a reference triangle using the defintion of the cosine function...

1 will be the hypotenuse and x will be the adjacent side....

solve for the opposite side using the pythagorean theorem.

$x^2+(opp)^2=1^2$

$opp=\sqrt{1-x^2}$

Using the definition of tangent gives

$tan(\theta)=\frac{opp}{adj}=\frac{\sqrt{1-x^2}}{x}$

**TheEmptySet** · February 24th 2008, 09:16 AM

For the second part....

We need to know the domain of the arc cosine function....

The domain is 0 to Pi.

also note that the cosine function is even ie

$cos(-\theta)=cos(\theta)$

This gives us

$cos\left(\frac{-\pi}{7}\right)=cos\left(\frac{\pi}{7}\right)$

so

$cos^{-1}(cos\left(\frac{\pi}{3}\right))=\frac{\pi}{3}$

and

$cos^{-1}(cos\left(\frac{-\pi}{7}\right))=cos^{-1}(cos\left(\frac{\pi}{7}\right))=\frac{\pi}{7}$

since the angle is now in the domain of the arc sine function.

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