Point P is on the terminal side of angle theta. Evaluate the six trigonometric function of theta.
A.(12,7)
B.(4,9)
This creates a right triangle with one vertex at the origin..
using the pythagorean theorem
$\displaystyle 12^2+7^2=c^2$
$\displaystyle 144+49=c^2$
so...
$\displaystyle \sqrt{203}=c$
using the defintion of the trig functions...
$\displaystyle sin(\theta)=\frac{opposite}{hypotenuse}=\frac{7}{\ sqrt{203}}$
all of the others can be solved in a similar fashion
Yes try drawing a graph. Both will be right triangles.
You can draw a reference triangle for any point in the xy plane...
always draw the perpendicular to the x-axis. The hypotenuse will always be the line segment from the origin to the point.