2sin^2(x)-sin(x)=3 find for all values of x. this is pre-calc stuff.
what would i do from there...i have no clue what is going on in my pre-calc class right now so if some1 can just post every step, that would be really helpful and i have a couple more problems similar to this one and me seeing each step will help me with those.
Simple yes or no answers to my questions would have been useful in pinpointing your exact troubles.
Your mathematical difficulties seem to extend beyond trigonometry - you're encouraged to get as much extra help as possible from your instructor.
And the answer is where n is an integer.
Of course, the door is big enough. (Do you think that you scare us with such comment, rating's site will decay?)
2 sin^2(x) - sin(x) = 3
2 sin ^2(x) - sin(x) - 3 = 0
2y^2 - y - 3 = 0
(2y-3)(y+1) = 0
sin x = 3/2 and -1
since -1 <= sin <= 1
sin x = -1
x = sin^-1 (-1)
x = 3pi / 2 + 2pi(n) where n is an element of Z
sorry if im wrong =[ but like that seems right XD
I think your answer is solved for = 1 not = 3
edit .. or you used 1 instead of -1 ... ?
sorry if im wrong >.>