1. ## Trig-trouble

Hi everyone,

I've got a little trig-trouble here..

What I know:

AB = 8 [mm]
CD = 1 [mm]
DE = 2 [mm]
EF = 4 [mm]
FG = 5 [mm]
HA = 10 [mm]
ABC = 100 [°]
BCD = 90 [°]
DEF = 90 [°]
EFG = 90 [°]
GHA = 130 [°]
HAB = 60 [°]

I need to calculate the distance AE. Any idea?

B.

2. ## Re: Trig-trouble

Well, too many "points...angles...lines" for me to refer to without a schoolroom blackboard!

Here's a hint:
Draw perpendicular HK (K on AB) to AB;
right triangle AHK = 30-60-90, so AK = 5.

Good luck...

3. ## Re: Trig-trouble

Originally Posted by DenisB
Well, too many "points...angles...lines" for me to refer to without a schoolroom blackboard!

Here's a hint:
Draw perpendicular HK (K on AB) to AB;
right triangle AHK = 30-60-90, so AK = 5.

Good luck...
Angle HAB is 60 degrees, not angle HAE.

But you're right. This thing needs a blackboard to do it properly. If I had a CAD program I might try it.

-Dan

4. ## Re: Trig-trouble

Originally Posted by topsquark
Angle HAB is 60 degrees, not angle HAE.
True...BUT what I did is still correct...it simply is a POOR hint!!