Hi everyone, I've got a little trig-trouble here.. What I know: AB = 8 [mm] CD = 1 [mm] DE = 2 [mm] EF = 4 [mm] FG = 5 [mm] HA = 10 [mm] ABC = 100 [°] BCD = 90 [°] DEF = 90 [°] EFG = 90 [°] GHA = 130 [°] HAB = 60 [°] I need to calculate the distance AE. Any idea? Thanks in advance! B.
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Well, too many "points...angles...lines" for me to refer to without a schoolroom blackboard! Here's a hint: Draw perpendicular HK (K on AB) to AB; right triangle AHK = 30-60-90, so AK = 5. Good luck...
Originally Posted by DenisB Well, too many "points...angles...lines" for me to refer to without a schoolroom blackboard! Here's a hint: Draw perpendicular HK (K on AB) to AB; right triangle AHK = 30-60-90, so AK = 5. Good luck... Angle HAB is 60 degrees, not angle HAE. But you're right. This thing needs a blackboard to do it properly. If I had a CAD program I might try it. -Dan
Originally Posted by topsquark Angle HAB is 60 degrees, not angle HAE. True...BUT what I did is still correct...it simply is a POOR hint!!