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Thread: Why is sin^2(x) [aka sin(x)^2] plotted the way it is?

  1. #1
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    Why is sin^2(x) [aka sin(x)^2] plotted the way it is?

    I compared the equation to sin^2(x) to sin(x) and I noticed a vast difference. The graphs below provide more insight:
    Why is sin^2(x) [aka sin(x)^2] plotted the way it is?-hillsin-2x.jpgsin^2(x) and Why is sin^2(x) [aka sin(x)^2] plotted the way it is?-sinx.jpg sin(x)

    I understand that two maximums on the sin(x) graphs (positive side) mean that one full rotation of the circle occurred, with the domain for now being 180 degrees or pi.
    However, I cannot grasp why sin^2(x) does not contain a minimum below zero... can someone explain this to me?
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  2. #2
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    Re: Why is sin^2(x) [aka sin(x)^2] plotted the way it is?

    you're asking why the square of a real number is never below zero?
    Thanks from topsquark and bossbasslol
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  3. #3
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    Re: Why is sin^2(x) [aka sin(x)^2] plotted the way it is?

    That's what it was. :<|, thanks!
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