Results 1 to 3 of 3
Like Tree2Thanks
  • 2 Post By Plato

Thread: Solving Trigonometric Equations

  1. #1
    Newbie
    Joined
    Mar 2019
    From
    United States
    Posts
    14

    Solving Trigonometric Equations

    Can anyone solve this and walk me through how you got your answer?

    2sin(2x)-2sinx+2√3 cosx-√3 =0
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    22,405
    Thanks
    3296
    Awards
    1

    Re: Solving Trigonometric Equations

    Quote Originally Posted by TrinityHarvin View Post
    Can anyone solve this and walk me through how you got your answer?
    2sin(2x)-2sinx+2√3 cosx-√3 =0
    $\displaystyle \left\{ \begin{array}{l}2\sin(2x)-2\sin(x)+2\sqrt3\cos(x)-\sqrt3=0\\4\sin(x)\cos(x)-2\sin(x)+2\sqrt3\cos(x)-\sqrt3=0\\2\sin(x)[2\cos(x)-1]-\sqrt3\left[2\cos(x)-1\right]=0\\\large(2\sin(x)-\sqrt3)(2\cos(x)-1)=0\end{array} \right.$
    Thanks from topsquark and TrinityHarvin
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2019
    From
    United States
    Posts
    14

    Re: Solving Trigonometric Equations

    Woah! Thanks!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Solving trigonometric equations:
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: Aug 12th 2011, 10:15 AM
  2. Solving trigonometric equations
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: May 11th 2011, 05:20 PM
  3. Solving Trigonometric equations
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: Mar 28th 2009, 01:08 AM
  4. Solving Trigonometric Equations Exactly
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: Jun 12th 2008, 03:52 AM
  5. Solving trigonometric equations
    Posted in the Pre-Calculus Forum
    Replies: 7
    Last Post: Feb 27th 2008, 04:34 AM

/mathhelpforum @mathhelpforum