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Thread: How do you describe the fact that all triangle with base are measure of theta

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    How do you describe the fact that all triangle with base are measure of theta

    How do you describe the fact that all triangles with base one are measure of theta(an angle)? The only reason I can think of is because the base is one.

    I have three measures of three altitudes $h_0,h_1,h_2$ where sides $a,b,c$ are the constant lengths of all triangles and base $c=1$ and $h_0$ is situated on base $c$.
    $\frac{h_0}{h_1}=b$,$\frac{h_0}{h_2}=a$ and $ h_1=\sin A$ as well $h_2=\sin B$.

    $\frac{a}{\sin C}=\frac{b}{\sin B}=\frac{c}{\sin C}=d$

    $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=\frac{1}{d}$

    d=diameter

    $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=\frac{1}{d}$

    if I mutiply by d (the diameter) it will give an answer of 1, and 1 is the base. And if I multiply the base times 4, all of 3 sides are a multiple of 4 including the altitudes. d=diameter

    How do you describe the fact that all triangle with base are measure of theta-screenshot_2019-01-01-09-09-17.png
    Last edited by Larrousse; Jan 1st 2019 at 02:14 PM.
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