When I enter my equation into my graphing calculator it's not looking like the graph in my attachment. I would like to know where I am going wrong..

So what I do know is that this graph is of the form y= asin(bx + c) +d. The graph has been raised by one unit so I know that d =1 and that a=1 as well. The period of the function is calculated by using the formula p= 2pi/b. So to figure this out I looked to see where this graph completed one full cycle. It looks like the cycle begins at x =-1 to x = 6. So I set my period to be 7 and from that I solved for b. b= 2pi/7. To find my phase shift I set bx+c=0 and from that c= 2pi/7? My final answer then for this problem is y = sin((2pi/7)× +2pi/7)+ 1? So where did i go wrong?