Please help me with this problem. I have to rewrite it as y=???? Sent from my iPhone using Tapatalk
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Originally Posted by Ema453 Please help me with this problem. I have to rewrite it as y=???? Sent from my iPhone using Tapatalk $\displaystyle x = 7^{y + 1}$ Take the $\displaystyle log_7$ of both sides: $\displaystyle log_7 (x) = log_7 \left ( 7^{y + 1} \right ) = y + 1$ Can you finish from here? -Dan
Or, if you need a decimal answer and your calculator doesn't do $\log_7$, just take the natural log of both sides in the first place.
TATTOO this on your wrist (under your watch!) : "if a^x = b, then x = log(b)/log(a)"