# Thread: Hi, I have tried to work out the following...

1. ## Hi, I have tried to work out the following...

...can someone help me. Sine cosine tangent angles

i have attached the following

2. ## Re: Hi, I have tried to work out the following...

This is not a classroom.

Go here:

Come back if you need more help...

3. ## Re: Hi, I have tried to work out the following...

Originally Posted by Jaz
...can someone help me. Sine cosine tangent angles

i have attached the following

There isn't really much help we can give.

$\displaystyle sin( \theta ) = \frac{ \text{opposite} }{ \text{hypotenuse} }$

$\displaystyle cos( \theta ) = \frac{ \text{adjacent} }{ \text{hypotenuse} }$

$\displaystyle tan( \theta ) = \frac{ sin( \theta ) }{ cos( \theta ) } = \frac{ \text{opposite} }{ \text{adjacent} }$

So for 1a)
$\displaystyle sin(x) = \frac{AC}{BC}$

$\displaystyle cos(x) = \frac{AB}{BC}$

$\displaystyle tan(x) = \frac{AC}{AB}$