...can someone help me. Sine cosine tangent angles
i have attached the following
thanks in advance!
This is not a classroom.
Go here:
https://www.khanacademy.org/math/geo...cosines-review
Come back if you need more help...
There isn't really much help we can give.
$\displaystyle sin( \theta ) = \frac{ \text{opposite} }{ \text{hypotenuse} }$
$\displaystyle cos( \theta ) = \frac{ \text{adjacent} }{ \text{hypotenuse} }$
$\displaystyle tan( \theta ) = \frac{ sin( \theta ) }{ cos( \theta ) } = \frac{ \text{opposite} }{ \text{adjacent} }$
So for 1a)
$\displaystyle sin(x) = \frac{AC}{BC}$
$\displaystyle cos(x) = \frac{AB}{BC}$
$\displaystyle tan(x) = \frac{AC}{AB}$
We'll be happy to check your answers but if you have further troubles the best person to ask is likely your instructor.
-Dan