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Thread: Hi, I have tried to work out the following...

  1. #1
    Jaz
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    Hi, I have tried to work out the following...

    ...can someone help me. Sine cosine tangent angles

    i have attached the following

    thanks in advance!
    Attached Thumbnails Attached Thumbnails Hi, I have tried to work out the following...-39aa87f4-ad84-44a6-ba54-dc49a7c3f3ec.jpeg   Hi, I have tried to work out the following...-2d165e02-e5b2-4db7-8a66-f7de34670f2a.jpeg  
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  2. #2
    MHF Contributor
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    Re: Hi, I have tried to work out the following...

    This is not a classroom.

    Go here:
    https://www.khanacademy.org/math/geo...cosines-review

    Come back if you need more help...
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    Forum Admin topsquark's Avatar
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    Re: Hi, I have tried to work out the following...

    Quote Originally Posted by Jaz View Post
    ...can someone help me. Sine cosine tangent angles

    i have attached the following

    thanks in advance!
    There isn't really much help we can give.

    $\displaystyle sin( \theta ) = \frac{ \text{opposite} }{ \text{hypotenuse} }$

    $\displaystyle cos( \theta ) = \frac{ \text{adjacent} }{ \text{hypotenuse} }$

    $\displaystyle tan( \theta ) = \frac{ sin( \theta ) }{ cos( \theta ) } = \frac{ \text{opposite} }{ \text{adjacent} }$

    So for 1a)
    $\displaystyle sin(x) = \frac{AC}{BC}$

    $\displaystyle cos(x) = \frac{AB}{BC}$

    $\displaystyle tan(x) = \frac{AC}{AB}$

    We'll be happy to check your answers but if you have further troubles the best person to ask is likely your instructor.

    -Dan
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