# Thread: Thinking Question Help plz

1. ## Thinking Question Help plz

Hi guys, so i need a plan to execute the steps and follow these criterias but i cant even get a head start. Any help would be much appreciated. Thanks guys!

Two rational variable expressions are divided and the simplified expression must meet the following conditions:

—The simplified expression's denominator is a linear expression while the numerator is a quadratic expression
—The simplified expression's numerator must contain a factor of (3�� − 5)
—The restrictions for the expressions must include �� ≠ −2, 3

2. ## Re: Thinking Question Help plz

Originally Posted by Bvs
Hi guys, so i need a plan to execute the steps and follow these criterias but i cant even get a head start. Any help would be much appreciated. Thanks guys!

Two rational variable expressions are divided and the simplified expression must meet the following conditions:

—The simplified expression's denominator is a linear expression while the numerator is a quadratic expression
Do know what these words mean? Since we have "denominator" and "numerator" we must have a fraction. A "linear expression" is of the form "ax+ b" and a "quadratic expression" is of the form "cx^2+ dx+ e" where a, b, c, d, and e are specific numbers.

—The simplified expression's numerator must contain a factor of (3�� − 5)
You seem to have a symbol here that does not show on my computer. I will assume that was simply "3x- 5". Since the numerator must a 'quadratic expression' with that factor, it must be of the form (3x- 5)(px+ q).

—The restrictions for the expressions must include �� ≠ −2, 3
Now this one puzzles me. The only "restriction" for a fraction is that the denominator cannot be 0. But since the denominator is to be a "linear expression", of the form ax+ b, there is only one number, -b/a, that would make the denominator 0, not two.

3. ## Re: Thinking Question Help plz

$\displaystyle \dfrac{(3x-5)(x-3)(x+4)}{(x-3)(x+2)}$ simplifies to $\displaystyle \dfrac{3x^2+7x-20}{x+2}$ when $\displaystyle x \neq 3$.