Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By SlipEternal

Thread: integrals of inverse trig

  1. #1
    Newbie Wattssan's Avatar
    Joined
    Apr 2017
    From
    Melling
    Posts
    8
    Thanks
    1

    integrals of inverse trig

    show that sec-1=cos-1(1/x)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Nov 2010
    Posts
    3,634
    Thanks
    1458

    Re: integrals of inverse trig

    Quote Originally Posted by Wattssan View Post
    show that sec-1=cos-1(1/x)
    That question does not make sense. You cannot apply an inverse trigonometric function to an equals sign.

    Do you mean $\sec^{-1} x = \cos^{-1}\left( \dfrac{1}{x} \right)$?

    $y = \sec^{-1} x \Longrightarrow x = \sec y \Longrightarrow \dfrac{1}{x} = \cos y \Longrightarrow y = \cos^{-1}\left( \dfrac{1}{x}\right)$

    This is not a question of integration, so I do not understand the title of your post.
    Thanks from Wattssan
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Aug 2006
    Posts
    21,967
    Thanks
    2921
    Awards
    1

    Re: integrals of inverse trig

    Quote Originally Posted by Wattssan View Post
    show that sec-1(?)=cos-1(1/x)
    There is something missing in the post.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: Feb 3rd 2010, 02:25 PM
  2. Integrals Involving Inverse Trig Functions
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Sep 12th 2009, 09:51 PM
  3. Evaluating Integrals (inverse trig functions)
    Posted in the Calculus Forum
    Replies: 3
    Last Post: Apr 22nd 2009, 03:31 PM
  4. inverse trig values and finding inverse
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: Apr 6th 2009, 12:04 AM
  5. Inverse Trig Function Integrals
    Posted in the Calculus Forum
    Replies: 6
    Last Post: Dec 2nd 2006, 05:54 AM

/mathhelpforum @mathhelpforum