# Math Help - tan(pi/12)

1. ## tan(pi/12)

How do I find the answer to tan(pi/12)? I wouldn't be surprised if this was something really simple that just slipped by me...

2. Try the identity:

$tan(\frac{u}{2})=\frac{1-cos(u)}{sin(u)}=\frac{sin(u)}{1+cos(u)}$

Where $u=\frac{\pi}{6}$

3. $\frac{\pi }{3} - \frac{\pi }{4} = \frac{\pi }{{12}}$

4. thanks! that helped a lot! ;D